9y^2+12y-10=0

Solution for 9y^2+12y-10=0 equation:

9y^2+12y-10=0

a = 9; b = 12; c = -10;
Δ = b2-4ac
Δ = 122-4·9·(-10)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6\sqrt{14}}{2*9}=\frac{-12-6\sqrt{14}}{18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6\sqrt{14}}{2*9}=\frac{-12+6\sqrt{14}}{18}
$